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  • ...intervals or, moreover, of $1$-''chains''. We can see this idea in the new form of the additivity property: ...s. The form on the left is what we call the ''exterior derivative'' of the form on the right.
    34 KB (5,619 words) - 16:00, 30 November 2015
  • *[[cubical form|cubical form]] *[[differentiable form|differentiable form]]
    16 KB (1,773 words) - 00:41, 17 February 2016
  • where $f:R \to R$ is continuous and $x:I \to R$ is differentiable on an open interval $I$. The equation has to be satisfied for all $t \in I$ ...ut $dx$ its [[exterior derivative]], a $1$-form, and $dt$ the constant $1$-form.
    9 KB (1,561 words) - 16:06, 27 August 2015
  • *Solve the following system, expressing the solution in vector form: $$\begin{array}{lll}x_2-x_3=1,\\x_1+x_2+x_3=2.\end{array}$$ **c. If the partial derivatives exist then the function is differentiable.
    14 KB (2,538 words) - 18:35, 14 October 2017
  • These two sequences of numbers form a sequence of intervals: Thus to compare two functions $f$ and $g$, at infinity or at a point, we form a fraction from them and evaluate the limit of the ratio:
    59 KB (10,063 words) - 04:59, 21 February 2019
  • ...$f$ is [[continuous]]. But if $b > 1 + \frac{a}{2} \pi$, $f$ is nowhere [[differentiable]]. (For another example, consider the issue of [[lengths of curves]] in the | $0$-form
    10 KB (1,471 words) - 12:50, 12 August 2015
  • ...rem ([[Mean Value Theorem]]).''' Let $[ a, b ] \subset D(h)$, where $h$ is differentiable on $( a, b )$ and $h$ is continuous on $[ a, b ]$. Then ...f which isn't true. This is what it does and does not say about a function differentiable at $X=C$:
    7 KB (1,171 words) - 20:28, 10 July 2018
  • '''Definition:''' Given a $0$-form $\varphi$, the ''integral of the form $\varphi$ over oriented $0$-manifold'' $M=\{p\}$ is: *$0$-form $=$ number assigned to each vertex.
    12 KB (1,906 words) - 17:44, 31 December 2012
  • Recall, a continuous $1$-form in ${\bf R}^3$ is a function ...$(dx,dy,dz)$. The function is [[linear operator|linear]] on $dx,dy,dz$, [[differentiable]] on $x,y,z$.
    6 KB (1,177 words) - 15:53, 5 November 2012
  • *right then down: we acquire a $0$-form $g$ by sampling function $f$, and then we acquire $dg$ by taking the differ ...he derivative $f'$ of $f$, and then we find the exterior derivative (a $1$-form) $dg$ by integrating $f'$ on the segments:
    21 KB (3,664 words) - 02:02, 18 July 2018
  • ...e domain and a new edge for each node. Together, these new nodes and edges form a new copy of the domain. [[image:form and its dual.png| center]]
    64 KB (11,521 words) - 19:48, 22 June 2017
  • ...hat, continuous and discrete forms are very similar in the sense that they form vector spaces that behave similarly. ...on we need to be able to match two very different entities -- a continuous form and a discrete one -- one by one. Let's review what they are.
    9 KB (1,483 words) - 13:54, 13 April 2013
  • provided $x=x(t),\ y=y(t)$ are differentiable at $t$ and $u=f(x,y),\ v=g(x,y)$ are continuous at $(x(t),y(t))$. ...ir of functions $x=x(t)$ and $y=y(t)$ (a parametric curve) with either one differentiable on an open interval $I$ such that for every $t$ in $I$ we have:
    63 KB (10,958 words) - 14:27, 24 November 2018
  • ...(Topological property of exterior derivative).''' If $\varphi$ is a $C^2$-form in $\Omega ^k({\bf R}^n)$, then $d_{k+1}(d_k \varphi)=0$ (we can also write ...uct]] and $A=A(x^1,...,x^n)$ is a coefficient function, twice continuously differentiable. Then, using the definition of exterior derivative and its formula for $0$-
    9 KB (1,423 words) - 20:53, 13 March 2013
  • The four coefficients of $x,y$ form the first table: Now form a matrix:
    46 KB (7,625 words) - 13:08, 26 February 2018
  • ...al "generically". They are usually required to be [[continuous]] or even [[differentiable]]. Recall $y = f(x)$ is a $0$-form and $dy=f'(x)dx$ is a $1$-form.
    10 KB (1,588 words) - 17:11, 27 August 2015
  • ...[[First derivative test]]).''' Suppose $a$ is a local extreme point of a [[differentiable function]] $f$. Then which form a line.
    9 KB (1,511 words) - 16:07, 17 August 2011
  • : for any [[differentiable function]] $f\cdot g$ wrt $x$. : for differentiable $f$ and $g$.
    6 KB (1,004 words) - 16:00, 2 May 2011
  • ...aled versions of the old ones. Let's recast this statement in the integral form. ...ched versions of the old ones. Let's recast this statement in the integral form:
    69 KB (11,727 words) - 03:34, 30 January 2019
  • where $A,B$ are continuously differentiable functions and $dX,dY$ are basis elements of $ \Omega^k,\Omega^m$ respective '''Theorem.''' $d(d\varphi) = 0$ for any $C^2$-form $\varphi \in \Omega^k$.
    8 KB (1,539 words) - 18:17, 22 August 2015
  • ...which is a [[differential form]] of degree $1$, for the same purpose. This form is ''defined'' on the tangent vectors to the domain manifold. We now invest ...n. Let's parametrize $C$ as $p \colon [a,b] \rightarrow C$, where $p$ is [[differentiable]].
    5 KB (859 words) - 02:33, 22 January 2013
  • ...st derivative test in dim n).''' Suppose a is a local extreme point of a [[differentiable function]] f. Then which form a line.
    3 KB (438 words) - 19:02, 7 August 2010
  • ...restriction of $f$ to $L, D(g) = L$. Now every element $v$ in $L$ has the form The idea comes from the fact that if you zoom in on the graph of a [[differentiable function]], it looks like a straight line.
    34 KB (5,636 words) - 23:52, 7 October 2017
  • Recall that we have $n$ commodities freely traded with possible prices that form a ''price vector'' $p=(p_1,...,p_n),$ at each moment of time. Then all posi under some norm so that the new prices form the $n$-simplex $\sigma$.
    41 KB (7,169 words) - 14:00, 1 December 2015
  • ...by $C^0(G)$ and $C^1(G)$ respectively (not to be confused with the set of differentiable functions). ...cochains are called ''discrete differential forms''<!--\index{differential form}-->, to be discussed later.
    16 KB (2,578 words) - 00:14, 18 February 2016
  • Assume $f$ is [[differentiable]] at $x=a$. In that case, when you zoom in on the point, the tangent line w [[Point-slope]] form:
    2 KB (384 words) - 15:44, 2 May 2011
  • ...half-disk but, when it's glued to its antipodal point, the two half-disks form a whole disk. Let's classify the level sets of a twice [[differentiable]] function.
    9 KB (1,542 words) - 19:58, 21 January 2014
  • The idea comes from the fact that if you zoom in on the graph of a [[differentiable function]], it looks like a straight line. Let $f: {\bf R}^n {\rightarrow} {\bf R}^m$. What is the form of $T$?
    7 KB (1,162 words) - 03:25, 22 August 2011
  • ...o {\bf R}^n$ is a continuous [[vector field]] and $x:I \to {\bf R}^n$ is a differentiable [[parametric curve]] defined on an open interval $I$. and a vector-valued $0$-form.
    2 KB (377 words) - 17:13, 27 August 2015
  • '''Exercise.''' In addition to being continuous, $f(x)=x^2$ is also differentiable. How does that help with the accuracy issue? Hint: there is a simple depend ...to algebra, it will explain how these pieces fit together ''globally'' to form components<!--\index{path-component}-->, holes<!--\index{holes}-->, voids<!
    17 KB (2,946 words) - 04:51, 25 November 2015
  • Therefore, the balance equation has this form: Now, something a bit more specific. What if these points form the graph of a function $y=f(x)$ defined at the nodes of a partition of $[a
    103 KB (18,460 words) - 01:01, 13 February 2019
  • *Find the reduced row echelon form of the following system of linear equations. What kind of set is its soluti ...${\bf R}^2$ that are orthogonal to $<-1,3>$. Write the set in the standard form of a line through the origin.
    46 KB (8,035 words) - 13:50, 15 March 2018
  • ...exists (it does when $F$ is [[continuous]] and the curve is continuously [[differentiable]]), then we define the ''line integral'' as this limit (here $F \cdot V ds$ is a [[differential form]]).
    15 KB (2,545 words) - 19:47, 20 August 2011
  • #Suppose $V$ is the space of differentiable at $0$ functions of two variables. Suppose $A:V\longrightarrow \mathbf{R}^{ Form a matrix from these columns.
    4 KB (583 words) - 01:13, 12 October 2011
  • *2. $\frac{d}{dx} \colon C^1({\bf R}) \rightarrow ?$, (from the [[differentiable]] functions to what?) ...row {\bf R}$: $f'(a)=3$, or $\frac{dy}{dx}=3$, or $dy=3dx$ ([[differential form]]).
    13 KB (2,187 words) - 22:17, 9 September 2011
  • This looks very much like the definition of a $2$-form except it's ''symmetric not antisymmetric''! if $C$ is parametrized by a differentiable function $p:[a,b] \rightarrow {\bf R}^n$. We can also compute the [[curvatu
    9 KB (1,604 words) - 18:08, 27 August 2015
  • ...and $B$ are ''homologous'' if there is a surface $S$ such that $A$ and $B$ form its boundary. *$F$ is differentiable on $X$,
    21 KB (3,530 words) - 19:54, 23 June 2015
  • ...and $B$ are ''homologous'' if there is a surface $S$ such that $A$ and $B$ form its boundary. *$F$ is differentiable on $X$,
    21 KB (3,581 words) - 15:51, 28 November 2015
  • ...this surface. The homotopy above is piece-wise linear and the one below is differentiable: '''Exercise.''' Prove that pointed spaces and pointed maps form a category.
    46 KB (7,846 words) - 02:47, 30 November 2015
  • ...$\alpha$. choose a single element of $\gamma$ that contains it. These sets form a finite subcover of $\gamma$. $\blacksquare$ Hint: To understand the concept, limit the set to differentiable functions with the derivatives between, say, $-1$ and $1$.
    19 KB (3,207 words) - 13:06, 29 November 2015
  • The [[point-slope form]] of the line: We say that $f$ isn't ''[[differentiable]]''.
    5 KB (857 words) - 13:57, 25 May 2011
  • ...s of a linear space. (b) Show that the vectors $(1,0,0), (1,1,0), (1,1,1)$ form a basis of ${\bf R}^3$. #Let $F$ be a differentiable parametric curve. If $F^{\prime}(t)$ is perpendicular to $F(t)$ for all $t,
    7 KB (1,394 words) - 02:36, 22 August 2011

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