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Dual cells and dual forms

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Duality in ${\bf R}^2$

What is the dual of a cell on the plane?

We define the dual grid "outside the box" with the same idea: the dual of a cell has the same center.

For a $2$-cell, the dual is its center:

HodgeFor2Cells.png

Each $k$-cell (primary) $\alpha$ corresponds to a $(2-k)$-cell (dual) $\alpha^*$ with $\alpha^*$ centered at the center of $\alpha$.

HodgeFor2Cells2.png

Important observation:

Theorem. For any cell, $$\alpha^{**}=\alpha$$

Therefore for the whole plane, it's simple:

Duality of the whole plane.png

What happens if we have non-trivial cubical complex $R \subset {\bf R}^2$? Some extra work is required as the example shows:

HodgeForRsubsetR2.png

So, in general, $$R^{**} \neq R.$$

Example: Let's verify $(dx)^* = dy$, $(dy)^*=dx$.

HodgeFordx.png

For either one, just turn $90^o$ and assign the same number (in the case of Euclidean geometry).

To be exact, this is how we find the values on $1$-cell for $(dx)^*$:

  • vertical dual cells $1 \longleftrightarrow 1$ horizontal primary cells.
  • horizontal dual cells $0 \longleftrightarrow 0$ vertical primary cells.

We find $(dx)^*$ from definition above, $(dx)^*(a) = dx(a^*)$, where $a$ is a dual cell and $a^*$ is a primary cell:

HodgeDualsVerticalAndHorizontal.png

Example: This is a $1$-form $\varphi$:

HodgeAOneForm.png

Find the $1$-form $\varphi^*$:

HodgeAOneFormItsDual.png

Duality in ${\bf R}^3$

There is more going on in ${\bf R}^3$:

HodgeDualsR3.png

Note: This looks very much like the orthogonal complement in linear algebra.