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- The [[point-slope form]] of the line: We say that $f$ isn't ''[[differentiable]]''.5 KB (857 words) - 13:57, 25 May 2011
- ...s of a linear space. (b) Show that the vectors $(1,0,0), (1,1,0), (1,1,1)$ form a basis of ${\bf R}^3$. #Let $F$ be a differentiable parametric curve. If $F^{\prime}(t)$ is perpendicular to $F(t)$ for all $t,7 KB (1,394 words) - 02:36, 22 August 2011