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- ...Hint: you'll have to prove first that the product of two closed subsets is closed. ...{\bf R}$ and the disks in ${\bf R}^2$ produce cylinders in ${\bf R}^3$ not balls. So, for the plan to work, we need to show that compactness holds even if w44 KB (7,951 words) - 02:21, 30 November 2015
- #[[Closed and exact forms]] #[[Open and closed sets]]16 KB (2,139 words) - 23:01, 9 February 2015
- *small balls connected by rods, or ...ma$ of $K$ as subsets of $|K|$ form a $\sigma$-algebra, i.e., a collection closed under the operations of complement, countable union, and countable intersec21 KB (3,445 words) - 13:53, 19 February 2016
- ...oods and topologies|base of the topology]] is the collection of all "open" balls in $X={\bf R}^n$: '''Theorem.''' A closed bounded subset of a [[Euclidean space]] is [[compactness|compact]].1 KB (201 words) - 14:41, 12 August 2018
- *small balls connected by rods, or ...ma$ of $K$ as subsets of $|K|$ form a $\sigma$-algebra, i.e., a collection closed under the operations of complement, countable union, and countable intersec20 KB (3,354 words) - 17:37, 30 November 2015
- ...e aren't included. This result it typical in the sense that the dual of a "closed" complex is an "open" complex. The solution is either to include in $K^*$ a *small balls connected by rods, or7 KB (1,114 words) - 18:10, 27 August 2015